2sin^2x=3(cosx+1)

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Solution for 2sin^2x=3(cosx+1) equation: 


Simplifying
2sin2x = 3(cosx + 1)

Reorder the terms:
2in2sx = 3(1 + cosx)
2in2sx = (1 * 3 + cosx * 3)
2in2sx = (3 + 3cosx)

Solving
2in2sx = 3 + 3cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Divide each side by '2n2sx'.
i = 1.5n-2s-1x-1 + 1.5cn-2o

Simplifying
i = 1.5n-2s-1x-1 + 1.5cn-2o

Reorder the terms:
i = 1.5cn-2o + 1.5n-2s-1x-1

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